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24w^2=6
We move all terms to the left:
24w^2-(6)=0
a = 24; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·24·(-6)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*24}=\frac{-24}{48} =-1/2 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*24}=\frac{24}{48} =1/2 $
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